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OP-00241 Solution claimed

Concave-function transfer of Frobenius low-rank error

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Let $A, \widehat A \in \mathbb{R}^{n \times n}$ be symmetric with $A \succeq \widehat A \succeq 0$ in the positive semidefinite order, and let $f : [0, \infty) \to [0, \infty)$ be continuous, concave and nondecreasing. For a symmetric positive semidefinite $X = \sum_{i=1}^n \lambda_i q_i q_i^{\mathsf T}$, with $q_1, \dots, q_n$ orthonormal and $\lambda_1 \ge \cdots \ge \lambda_n \ge 0$, put $$X_k = \sum_{i=1}^k \lambda_i q_i q_i^{\mathsf T}, \qquad f(X) = \sum_{i=1}^n f(\lambda_i)\, q_i q_i^{\mathsf T}, \qquad f(X)_k = \sum_{i=1}^k f(\lambda_i)\, q_i q_i^{\mathsf T},$$ so that $X_k$ and $f(X)_k$ use the same eigenvectors, which may be chosen arbitrarily within repeated eigenspaces. Let $\|M\|_F^2 = \sum_{i,j} M_{ij}^2$. Persson, Meyer and Musco proved the implication below when $f$ is in addition operator monotone, and noted that its premise, on a difference of squared norms, is stronger than $\|A - \widehat A_k\|_F^2 \le (1 + \varepsilon)\|A - A_k\|_F^2$.

Problem. Does $$\|A\|_F^2 - \|\widehat A_k\|_F^2 \le (1 + \varepsilon)\, \|A - A_k\|_F^2$$ imply $$\|f(A) - f(\widehat A)_k\|_F^2 \le (1 + \varepsilon)\, \|f(A) - f(A)_k\|_F^2$$ for all $n \ge 2$ and $1 \le k < n$, every such pair $A, \widehat A$, every such $f$, every choice of the eigendecompositions and every $\varepsilon \ge 0$?

Source: Persson, Meyer and Musco (2025), Table 1 (Frobenius norm, f concave and non-decreasing, A ⪰ Â) and Section 5; stated by OpenProblemsInNLA with the stronger premise of their Theorem 2.5.

Imported from github.com/ajt60gaibb/OpenProblemsInNLA.

Classification

Primary
NA — Numerical Analysis
Secondary
FA
Keywords
low-rank approximations, matrix functions, Nyström approximations, OpenProblemsInNLA
Literature checked
Oct. 8, 2026 by clemens-admin

References

@article{persson2025,
  author        = {Persson, David and Meyer, Raphael A. and Musco, Christopher},
  title         = {Algorithm-Agnostic Low-Rank Approximation of Operator Monotone Matrix Functions},
  journal       = {SIAM J. Matrix Anal. Appl.},
  volume        = {46},
  number        = {1},
  year          = {2025},
  pages         = {1--21},
  doi           = {10.1137/23M1619435},
  eprint        = {2311.14023},
  archivePrefix = {arXiv},
}
@article{persson2026,
  author        = {Persson, David and Chen, Tyler and Musco, Christopher},
  title         = {Randomized block-{K}rylov subspace methods for low-rank approximation of matrix functions},
  journal       = {Linear Algebra Appl.},
  volume        = {741},
  year          = {2026},
  pages         = {32--65},
  doi           = {10.1016/j.laa.2026.03.029},
  eprint        = {2502.01888},
  archivePrefix = {arXiv},
}
@misc{openproblemsinnla-ra09,
  author       = {Townsend, Alex},
  title        = {{RA-09}: Concave-function transfer of Frobenius low-rank error},
  howpublished = {Open Problems in Numerical Linear Algebra, GitHub repository},
  year         = {2026},
  url          = {https://github.com/ajt60gaibb/OpenProblemsInNLA/blob/main/randomized-and-low-rank-approximation/RA-09/README.md},
  note         = {Read at commit eb7c9d6, 2026-10-07},
}

Resolution claims

Matthew J. Colbrook

Let $f:[0,\infty)\to[0,\infty)$ be continuous and nondecreasing, with $f(x)/x$ nonincreasing on $(0,\infty)$. This class includes every nonnegative nondecreasing concave function. We prove that ordinary relative Frobenius approximation error transfers from $A$ to $f(A)$ without loss whenever $0\preceq B\preceq A$ and $B$ has the prescribed low rank. No operator-monotonicity assumption or stronger trace-deficit hypothesis is needed. Without the order assumption, the relative …

Full resolution · not verified · fidelity not established · posted on GitHub 11 Sep 2026

Status history

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2026-10-08 Needs verification → Solution claimed clemens-admin Listed with the record of its solution, unreviewed.

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OP-00241, "Concave-function transfer of Frobenius low-rank error", clopen.solutions.